(3x-1)(x^2-5x+4)=0

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Solution for (3x-1)(x^2-5x+4)=0 equation:


Simplifying
(3x + -1)(x2 + -5x + 4) = 0

Reorder the terms:
(-1 + 3x)(x2 + -5x + 4) = 0

Reorder the terms:
(-1 + 3x)(4 + -5x + x2) = 0

Multiply (-1 + 3x) * (4 + -5x + x2)
(-1(4 + -5x + x2) + 3x * (4 + -5x + x2)) = 0
((4 * -1 + -5x * -1 + x2 * -1) + 3x * (4 + -5x + x2)) = 0
((-4 + 5x + -1x2) + 3x * (4 + -5x + x2)) = 0
(-4 + 5x + -1x2 + (4 * 3x + -5x * 3x + x2 * 3x)) = 0
(-4 + 5x + -1x2 + (12x + -15x2 + 3x3)) = 0

Reorder the terms:
(-4 + 5x + 12x + -1x2 + -15x2 + 3x3) = 0

Combine like terms: 5x + 12x = 17x
(-4 + 17x + -1x2 + -15x2 + 3x3) = 0

Combine like terms: -1x2 + -15x2 = -16x2
(-4 + 17x + -16x2 + 3x3) = 0

Solving
-4 + 17x + -16x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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